Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
class Solution {
public:
int threeSumClosest(vector<int> &num, int target) {
sort(num.begin(), num.end());
int diff = INT_MAX;
int res = 0;
for(int i=0;i<num.size()-2;i++)
{
if(i && num[i] == num[i-1]) continue;
int start = i + 1;
int end = num.size() - 1;
while(start < end)
{
int sum = num[start] + num[end] + num[i];
if(sum == target)
{
return target;
}
int k = abs(sum-target);
if(k < diff)
{
diff = k;
res = sum;
}
sum > target ? end-- : start++;
}
}
return res;
}
};