Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
class Solution { public: int threeSumClosest(vector<int> &num, int target) { sort(num.begin(), num.end()); int diff = INT_MAX; int res = 0; for(int i=0;i<num.size()-2;i++) { if(i && num[i] == num[i-1]) continue; int start = i + 1; int end = num.size() - 1; while(start < end) { int sum = num[start] + num[end] + num[i]; if(sum == target) { return target; } int k = abs(sum-target); if(k < diff) { diff = k; res = sum; } sum > target ? end-- : start++; } } return res; } };