class MedianFinder {
priority_queue<int> up;
priority_queue<int, vector<int>, greater<int> > down;
public:
// Adds a number into the data structure.
void addNum(int num) {
if(up.empty() || num <= up.top()) {
up.push(num);
}
else if(down.empty() || num >= down.top()) {
down.push(num);
}
else {
up.push(num);
}
if(up.size() >= down.size() + 2) {
int t = up.top();
up.pop();
down.push(t);
}
else if(down.size() >= up.size() + 2){
int t = down.top();
down.pop();
up.push(t);
}
}
// Returns the median of current data stream
double findMedian() {
if(up.size() > down.size()) return up.top();
else if(down.size() > up.size()) return down.top();
return (up.top() + down.top())/2.0;
}
};
Showing posts with label heap. Show all posts
Showing posts with label heap. Show all posts
Tuesday, October 20, 2015
[LeetCode] Find Median from Data Stream
Question can be found https://leetcode.com/problems/find-median-from-data-stream/
Monday, May 11, 2015
[LintCode] Heapify
Given an integer array, heapify it into a min-heap array.
For a heap array A, A[0] is the root of heap, and for each A[i], A[i * 2 + 1] is the left child of A[i] and A[i * 2 + 2] is the right child of A[i].
Example
Given [3,2,1,4,5], return [1,2,3,4,5] or any legal heap array.
class Solution {
public:
void heapify(vector<int> &num)
{
int len = num.size();
int start = (len-2)/2;
while(start >= 0)
{
int root = start;
while(2*root+1 < len)
{
int swap = root;
int left = 2*root + 1;
int right = left + 1;
if(num[swap]>num[left]) swap = left;
if(right<len&&num[right]<num[swap]) swap = right;
if(swap == root) break;
int tmp = num[swap];
num[swap] = num[root];
num[root] = tmp;
root = swap;
}
start --;
}
}
};
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