Implement regular expression matching with support for
'.'
and '*'
.'.' Matches any single character.
'*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Example
isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "a*") → true isMatch("aa", ".*") → true isMatch("ab", ".*") → true isMatch("aab", "c*a*b") → true
class Solution { public: /** * @param s: A string * @param p: A string includes "." and "*" * @return: A boolean */ bool isMatch(const char *s, const char *p) { // write your code here if(*p == '\0') return *s == '\0'; if(*(p+1) == '*') { while(*p == *s || ((*p) == '.' && (*s) != 0)) { if(isMatch(s, p + 2)) return true; s++; } return isMatch(s, p + 2); } else { if (*s != '\0' && *p == *s || *p == '.') return isMatch(s+1, p+1); } return false; } };