Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array
the subarray
[2,3,1,2,4,3] and s = 7,the subarray
[4,3] has the minimal length under the problem constraint.
class Solution {
public:
int minSubArrayLen(int s, vector<int>& nums) {
int first = 0, second = 0, sum=0;
int minLen = INT_MAX;
while(first<nums.size())
{
if(sum>=s)
{
minLen = min(minLen, second-first);
sum -= nums[first++];
continue;
}
if(second == nums.size()) break;
sum += nums[second++];
}
return minLen == INT_MAX ? 0 : minLen;
}
};