Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as
1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is
2.
Note: m and n will be at most 100.
class Solution {
public:
int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) {
int m = obstacleGrid.size();
if(0 == m) return 0;
int n = obstacleGrid[0].size();
if(0 == n) return 0;
int paths[m][n];
paths[0][0] = obstacleGrid[0][0] == 1?0:1;
for(int i=1;i<m;i++)
{
if(obstacleGrid[i][0] == 1)paths[i][0] = 0;
else paths[i][0] = paths[i-1][0];
}
for(int i=1;i<n;i++)
{
if(obstacleGrid[0][i] == 1)paths[0][i] = 0;
else paths[0][i] = paths[0][i-1];
}
for(int i=1;i<m;i++)
{
for(int j=1;j<n;j++)
{
if(obstacleGrid[i][j] == 1) paths[i][j]=0;
else paths[i][j] =
paths[i-1][j] + paths[i][j-1];
}
}
return paths[m-1][n-1];
}
};