Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes' values.
For example,
Given
Given
{1,2,3,4}, reorder it to {1,4,2,3}.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *reverse(ListNode *p)
{
ListNode *ret = NULL;
while(p)
{
ListNode * t =p->next;
p->next = ret;
ret = p;
p = t;
}
return ret;
}
void reorderList(ListNode *head) {
if(!head) return;
int c = 0;
ListNode *p = head, *m=head;
ListNode *prev = head;
while(p)
{
p=p->next;
c++;
if(c%2==0)
{
prev = m;
m=m->next;
}
}
if(c<=2) return;
prev->next = NULL;
ListNode *r = reverse(m);
p = head;
ListNode dummy(0);
ListNode *ret = &dummy;
c = 0;
while(p&&r)
{
if(c%2 ==0)
{
ret->next = p;
ret = p;
p = p->next;
}
else
{
ret->next = r;
ret = r;
r = r->next;
}
c++;
}
if(p) ret->next = p;
else ret->next = r;
}
};