Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22, 5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void pathSum(TreeNode *root, int sum, vector<int> & rec, vector<vector<int> >& res)
{
if(!root) return;
rec.push_back(root->val);
if(!root->left && !root->right)
{
if(root->val == sum)
{
res.push_back(rec);
return;
}
}
if(root->left)
{
pathSum(root->left, sum - root->val, rec, res);
rec.pop_back();
}
if(root->right)
{
pathSum(root->right, sum - root->val, rec, res);
rec.pop_back();
}
}
vector<vector<int> > pathSum(TreeNode *root, int sum)
{
vector<vector<int> > res;
vector<int> rec;
pathSum(root, sum, rec, res);
return res;
}
};