Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22
,5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void pathSum(TreeNode *root, int sum, vector<int> & rec, vector<vector<int> >& res) { if(!root) return; rec.push_back(root->val); if(!root->left && !root->right) { if(root->val == sum) { res.push_back(rec); return; } } if(root->left) { pathSum(root->left, sum - root->val, rec, res); rec.pop_back(); } if(root->right) { pathSum(root->right, sum - root->val, rec, res); rec.pop_back(); } } vector<vector<int> > pathSum(TreeNode *root, int sum) { vector<vector<int> > res; vector<int> rec; pathSum(root, sum, rec, res); return res; } };