Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling
next() will return the next smallest number in the BST.
Note:
next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
class BSTIterator {
private:
stack<TreeNode*> st;
public:
BSTIterator(TreeNode *root) {
findLeft(root);
}
bool hasNext() {
if (st.empty()) return false;
return true;
}
int next() {
TreeNode* top = st.top();
st.pop();
if (top->right != NULL)
findLeft(top->right);
return top->val;
}
void findLeft(TreeNode* root)
{
TreeNode* p = root;
while (p != NULL)
{
st.push(p);
p = p->left;
}
}
};