Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST's shown below.
Given n = 3, your program should return all 5 unique BST's shown below.
1 3 3 2 1
\ / / / \ \
3 2 1 1 3 2
/ / \ \
2 1 2 3
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void generate(vector<TreeNode*> &res, int num, int offset)
{
if(0 == num)
{
res.push_back(NULL);
return;
}
if(1 == num)
{
TreeNode* node = new TreeNode(num+offset);
res.push_back(node);
return;
}
for(int i=1;i<=num;i++)
{
vector<TreeNode*> left, right;
generate(left, i - 1, offset);
generate(right, num - i, offset + i );
for(int j=0;j<left.size();j++)
{
for(int k=0;k<right.size();k++)
{
TreeNode *cur = new TreeNode(i+offset);
cur->left = left[j];
cur->right = right[k];
res.push_back(cur);
}
}
}
}
vector<TreeNode*> generateTrees(int n) {
vector<TreeNode*> res;
generate(res, n, 0);
return res;
}
};