Given a collection of intervals, merge all overlapping intervals.
For example,
Given
return
Given
[1,3],[2,6],[8,10],[15,18],return
[1,6],[8,10],[15,18].
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
static bool compare(Interval & i1, Interval & i2)
{
return i1.start < i2.start;
}
public:
vector<Interval> merge(vector<Interval>& intervals) {
sort(intervals.begin(), intervals.end(), compare);
int len = intervals.size();
vector<Interval> res;
if(0 == len) return res;
res.push_back(intervals[0]);
for(int i=1;i<len;i++)
{
Interval & cur = res[res.size()-1];
if(cur.end >= intervals[i].start)
{
cur.end = max(cur.end, intervals[i].end);
}
else
{
res.push_back(intervals[i]);
}
}
return res;
}
};